Please study Addition Sums. if you have not already done so.

There, we covered the process of adding three digit numbers with examples and exercise.

There, we restricted ourselves to addition of three digit numbers such that the resulting number is also three digit number.

That knowledge is a prerequisite here.

Here, we deal with four digit numbers.

We have already seen in decimal number system that the successor to 999 is 1000. i.e. 999 + 1 = 1000.

Let us present this addition in the vertical presentation by using the carry over method explained in two digit addition.

999
1
_{1}_{1}
----
1000
----

Here, in the units' place, 9 and 1 added gave 10.

0 is put in the units' place of the answer, below and 1 is carried over to the tens' place. (see the small 1 present below the digits in the tens' place.)

Now the 9 and the small 1 added gave 10. 0 is put in the tens' place of the answer and 1 is carried over to the hundreds' place. (see the small 1 present under the digits in the hundreds' place.)

Now the 9 and the small 1 added gave 10 which is directly put in the answer, to get 1000.

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Perform the addition of the numbers 1987, 865, 94, 7

Solution to Example 2 of Addition Problems :

While adding numbers of different number of digits, we have to be careful in putting the numbers one below the other.

All the digits of the units' place should come one below the other.

Similarly, all the digits of the tens' place should come one below the other.

All the digits of the hundreds' place should come one below the other.

And all the digits of the thousands' place should come one below the other.

See the vertical presentation of the process given below.

1987
865
94
7
_{2}_{2}_{1}
----
2953
----

See how the numbers 1987, 865, 94, 7 are placed one below the other, in the above presentation.

In 1987, 1 is in thousands' place, 9 is in hundreds' place, 8 is in tens' place and 7 is in units' place.

In 865, 8 is in thousands' place, 6 is in tens' place and 5 is in units' place.

In 94, 9 is in tens' place and 4 is in units' place.

In 7, 7 is in units' place.

All the digits of the units place have to come one below the other.

Thus, you find 7, 5, 4 and 7 one below the other in the units' place in the above presentation.

Similarly, you find 8, 6 and 9 one below the other in the tens' place in the above presentation.

You find 9 and 8 in the hundreds' place.

You find only 1 in the thousands' place.

First, the digits in the units' place are added ( 7 + 5 + 4 + 7) to get 23.

In this 23, 3 is placed in the units' place of the answer and 2 is placed under the digits in the tens' place.

Then, add the digits in the tens' place including the small 2 carried over from the units' place, (8 + 6 + 9 + 2 ) to get 25.

In this 25, 5 is placed in the tens' place of the answer and 2 is placed under the digits in the hundreds' place.

Then, add the digits in the hundreds' place including the small 2 carried over from the tens' place,(9 + 8 + 2 ) to get 19.

In this 19, 9 is placed in the hundreds' place of the answer and 1 is placed under the digits in the thousands' place.

Then, add the digits in the thousands' place including the small 1 carried over from the hundreds' place,(1 + 1) to get 2.

This 2 is placed in the thousands' place of the answer.

Thus, the answer is 2953.

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Exercise on Addition Problems

Do the following Addition Problems :

Perform the additions of the following numbers.

2785, 4987, 1200

7089, 613, 79, 4

2314, 907, 2500

6300, 1102, 1245

1101, 18, 12

6, 7, 1934, 607

1296, 2507, 254

1107, 101, 199

6733, 1055, 1019

8918, 100, 329

For Answers, see at the end of the page.

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