Learn/Teach
For details, see near

if you have not already done so.

There, we covered the process of adding three
digit numbers with examples and exercise.

There, we restricted ourselves to addition
of three digit numbers such that the
resulting number is also three digit number.

That knowledge is a prerequisite here.

Here, we deal with four digit numbers.

decimal number system
that the successor to 999 is 1000.
i.e. 999 + 1 = 1000.

Let us present this addition in the
vertical presentation by using the
carry over method explained in

```
999
1
1
1
----
1000
----
```

Here, in the units' place,
9 and 1 added gave 10.

0 is put in the units' place of the answer,
below and 1 is carried over to the
tens' place. (see the small 1 present
below the digits in the tens' place.)

Now the 9 and the small 1 added gave 10.
0 is put in the tens' place of the answer
and 1 is carried over to the hundreds' place.
(see the small 1 present under the digits
in the hundreds' place.)

Now the 9 and the small 1 added
gave 10 which is directly put in

We also saw in the

decimal number system,
that the four digit numbers
range from 1000 to 9999.

Knowing these numbers in figures and
in words is a prerequisite here.

When we add four digit numbers,
this carrying over will take
place, one place further.

Let us see some examples on Addition Problems.

### Example 1 of Addition Problems

numbers 1976, 2687, 3418.

Solution to Example 1 of Addition Problems :

See the vertical presentation
of the process given below.

```
1976
2687
3418
2
1
2
----
8081
----
```

First, the digits in the units' place
are added ( 6 + 7 + 8) to get 21.

In this 21, 1 is placed in the units'
place of the answer and 2 is placed
under the digits in the tens' place.

Then, add the digits in the tens'
place including the small 2
carried over from the units'
place,(7 + 8 + 1 + 2 ) to get 18.

In this 18, 8 is placed in the tens'
place of the answer and 1 is placed
under the digits in the hundreds' place.

Then, add the digits in the hundreds'
place including the small 1 carried
over from the tens' place,
(9 + 6 + 4 + 1 ) to get 20.

In this 20, 0 is placed in the hundreds'
place of the answer and 2 is placed under
the digits in the thousands' place.

Then, add the digits in the thousands'
place including the small 2 carried
over from the hundreds' place,
(1 + 2 + 3 + 2 ) to get 8.

This 8 is placed in the thousands'

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### Example 2 of Addition Problems

Example 2 of Addition Problems :

numbers 1987, 865, 94, 7

Solution to Example 2 of Addition Problems :

While adding numbers of different number
of digits, we have to be careful in
putting the numbers one below the other.

All the digits of the units' place
should come one below the other.

Similarly, all the digits of the tens'
place should come one below the other.

All the digits of the hundreds' place
should come one below the other.

And all the digits of the thousands'
place should come one below the other.

See the vertical presentation
of the process given below.

```
1987
865
94
7
2
2
1
----
2953
----
```

See how the numbers 1987, 865, 94, 7
are placed one below the other,
in the above presentation.

In 1987, 1 is in thousands' place, 9 is
in hundreds' place, 8 is in tens' place
and 7 is in units' place.

In 865, 8 is in thousands' place, 6 is
in tens' place and 5 is in units' place.

In 94, 9 is in tens' place
and 4 is in units' place.

In 7, 7 is in units' place.

All the digits of the units place
have to come one below the other.

Thus, you find 7, 5, 4 and 7
one below the other in the units'
place in the above presentation.

Similarly, you find 8, 6 and 9
one below the other in the tens'
place in the above presentation.

You find 9 and 8 in the
hundreds' place.

You find only 1 in the
thousands' place.

First, the digits in the units' place
are added ( 7 + 5 + 4 + 7) to get 23.

In this 23, 3 is placed in the units'
place of the answer and 2 is placed
under the digits in the tens' place.

Then, add the digits in the tens' place
including the small 2 carried over from the
units' place, (8 + 6 + 9 + 2 ) to get 25.

In this 25, 5 is placed in the tens'
place of the answer and 2 is placed
under the digits in the hundreds' place.

Then, add the digits in the hundreds' place
including the small 2 carried over from
the tens' place,(9 + 8 + 2 ) to get 19.

In this 19, 9 is placed in the hundreds'
place of the answer and 1 is placed under
the digits in the thousands' place.

Then, add the digits in the thousands' place
including the small 1 carried over from the
hundreds' place,(1 + 1) to get 2.

This 2 is placed in the

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Do the following Addition Problems :

the following numbers.

1. 2785, 4987, 1200
2. 7089, 613, 79, 4
3. 2314, 907, 2500
4. 6300, 1102, 1245
5. 1101, 18, 12
6. 6, 7, 1934, 607
7. 1296, 2507, 254
8. 1107, 101, 199
9. 6733, 1055, 1019
10. 8918, 100, 329

For Answers, see at the end of the page.

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