# ALGEBRA 2 FACTORING - USING FACTOR THEOREM AND SYNTHETIC DIVISION, EXAMPLES

Method of Factoring Polynomial before Algebra 2 Factoring
if you have not already done so.

Remainder Theorem, Factor Theorem
and explained the Method of factoring
with Example.

Here, we will apply the method to solve problems.
The knowledge of Synthetic Division is made use of here.
That knowledge is a prerequisite here.
So, please learn the method before proceeding further.

## Example 1 of Algebra 2 Factoring

Solve the following problem on Algebra 2 Factoring

Factorize 2x3 - 7x2 - 10x + 24

Solution to Example 1 of Algebra 2 Factoring

Let f(x) = 2x3 - 7x2 - 10x + 24
Here constant term = +24. Its factors are +1,-1,+2, -2, +3, -3, +4, -4, +6, -6, +8, -8, +12, -12, +24, -24. So we check witha = +1,-1,+2, -2, +3, -3, +4, -4, +6, -6, +8, -8, +12, -12, +24, -24 whether f(a) is zero or not.
f(1) = 2 - 7 -10 +24 = +9 ≠ 0; f(-1) = 2(-1)3 - 7(-1)2 -10(-1) -12 = -2 - 7 + 10 -12 = -11 ≠ 0;
f(2) = 2(2)3 - 7(2)2 - 10(2) + 24 ≠ 0;
f(-2) = 2(-2)3 - 7(-2)2 - 10(-2) + 24 = -16 -28 +20 + 24 = 0;
x -(-2) = (x + 2) is a factor of f(x).
Now let us divide f(x) = (2x3 - 7x2 - 10x + 24) by (x + 2) usingSynthetic Division (For detailed explanation of Synthetic Division see Example 1 above.)

```-2  |   +2    -7    -10    +24
|   +0    -4    +22    -24
|-----------------------------
|   +2    -11   +12    +0
```

∴ Quotient = (+2)x2 + (-11)x + (12) = 2x2 - 11x + 12
Thus, (2x3 - 7x2 - 10x + 24) ÷ (x + 2) = 2x2 - 11x + 12
∴ 2x3 - 7x2 - 10x + 24 = (x + 2)(2x2 - 11x + 12)
We can factorize 2x2 - 11x + 12 using the knowledge of factoring Polynomials of second degree.
2x2 - 11x + 12 = 2x2 - 8x - 3x + 12= 2x(x - 4) - 3(x - 4) = (x - 4)(2x - 3)

∴ (2x3 - 7x2 - 10x + 24) = (x + 2)(x - 4)(2x - 3).
Thus Factoring Polynomial 2x3 - 7x2 - 10x + 24 by using Factor Theorem gave the Factors as(x + 2)(x - 4)(2x - 3). Ans.

Here is a collection of proven tips,
tools and techniques to turn you into
a super-achiever - even if you've never
thought of yourself as a "gifted" student.

and remember large chunks of information
with the least amount of effort.

If you apply what you read from the above
collection, you can achieve best grades without
giving up your fun, such as TV, surfing the net,
playing video games or going out with friends!

Know more about the Speed Study System.

## Example 2 of Algebra 2 Factoring

Solve the following problem on Algebra 2 Factoring

Factorize 2x3 - 11x2 + 17x - 6

Solution to Example 2 of Algebra 2 Factoring

Let f(x) = 2x3 - 11x2 + 17x - 6
Here constant term = -6. Its factors are +1,-1,+2, -2, +3, -3, +6, -6. So we check witha = +1,-1,+2, -2, +3, -3, +6, -6 whether f(a) is zero or not.
f(1) = 2 - 11 +17 -6 = +2 ≠ 0; f(-1) = 2(-1)3 - 11(-1)2 +17(-1) -6 = -2 + 11 - 17 -6 = -14 ≠ 0;
f(2) = 2(2)3 - 11(2)2 +17(2) - 6 = 16 - 44 + 34 - 6 = 0;
x -(2) = (x - 2) is a factor of f(x).
Now let us divide f(x) = (2x3 - 11x2 + 17x - 6) by (x - 2) usingSynthetic Division (For detailed explanation of Synthetic Division see Example 1 above.)

```2  |   +2    -11    +17    -6
|   +0    +4     -14    +6
|-----------------------------
|   +2    -7     +3     +0
```

∴ Quotient = (+2)x2 + (-7)x + (3) = 2x2 - 7x + 3
Thus, (2x3 - 11x2 + 17x - 6) ÷ (x - 2) = 2x2 - 7x + 3
∴ 2x3 - 7x2 - 10x + 24 = (x - 2)(2x2 - 7x + 3)
We can factorize 2x2 - 7x + 3 using the knowledge of factoring Polynomials of second degree.
2x2 - 7x + 3 = 2x2 - 6x - x + 3= 2x(x - 3) - 1(x - 3) = (x - 3)(2x - 1)

∴ (2x3 - 11x2 + 17x - 6) = (x - 2)(x - 3)(2x - 1).
Thus Factoring Polynomial 2x3 - 11x2 + 17x - 6 by using Factor Theorem gave the Factors as(x - 2)(x - 3)(2x - 1). Ans.

Great Deals on School & Homeschool Curriculum Books

## Example 3 of Algebra 2 Factoring

Solve the following problem on Algebra 2 Factoring

Find a and b in order that x3 - 6x2 + ax + b is exactly divisible by x2 - 3x + 2

Solution to Example 3 of Algebra 2 Factoring

Let f(x) = x3 - 6x2 + ax + bWe can factorize x2 - 3x + 2 using the knowledge of factorization of Quadratic Polynomials.
x2 - 3x + 2 = x2 - x - 2x + 2= x(x - 1) - 2(x - 1) = (x - 1)(x - 2)
f(x)[ = x3 - 6x2 + ax + b] is exactly divisible by x2 - 3x + 2
⇒ f(x) is exactly divisible by (x - 1)(x - 2)
⇒ (x - 1) and (x - 2) are factors of f(x)
⇒ f(1) = 0 and f(2) = 0
f(1) = 1 - 6 + a + b = a + b - 5 = 0 ⇒ a + b = 5...........(i)
f(2) = (2)3 - 6(2)2 + a(2) + b = 8 - 24 + 2a + b = 2a + b - 16
f(2) = 0 ⇒ 2a + b - 16 = 0 ⇒ 2a + b = 16..........(ii)
(ii) - (i) gives (2a + b) - (a + b) = 16 - 5 ⇒ 2a + b - a - b = 11⇒ a = 11
Using this value of a in (i), we get
11 + b = 5 ⇒ b = 5 - 11 = -6
Thus a = 11, b = -6. Thus Factor Theorem in Factoring Polynomials helped us to find a and b,for x3 - 6x2 + ax + b to be exactly divisible by x2 - 3x + 2 as a = 11 and b = -6. Ans.

## Exercise on Algebra 2 Factoring

Solve the Following Problems on Algebra 2 Factoring :

1. Factorize x3 + 6x2 + 11x + 6
2. Factorize 2x3 - x2 - 15x + 18
3. Find l and m in order that x4 - x3 + lx2 + mx + 4 is exactly divisible by x2 - x - 2
For Answers See at the bottom of the Page.

## Progressive Learning of Math : Algebra 2 Factoring

Recently, I have found a series of math curricula
(Both Hard Copy and Digital Copy) developed by a Lady Teacher
who taught everyone from Pre-K students to doctoral students
and who is a Ph.D. in Mathematics Education.

This series is very different and advantageous
over many of the traditional books available.
These give students tools that other books do not.
Other books just give practice.
These teach students “tricks” and new ways to think.

These build a student’s new knowledge of concepts
from their existing knowledge.
These provide many pages of practice that gradually
increases in difficulty and provide constant review.

These also provide teachers and parents with lessons
on how to work with the child on the concepts.

The series is low to reasonably priced and include

Elementary Math curriculum

and

Algebra Curriculum.

## Answers to Exercise on Algebra 2 Factoring

Answers to the problems in Exercise
on Algebra 2 Factoring are given below.

1. (x + 1)(x + 2)(x + 3}
2. (x - 2)(2x - 3)(x + 3}
3. l = -4, m = 2

## Research-based personalized Math Help tutoring program : Algebra 2 Factoring

Here is a resource for Solid Foundation in
Math Fundamentals from Middle thru High School.
You can check your self by the

### FREE TRIAL.

Are you spending lot of money for math tutors to your
child and still not satisfied with his/her grades ?

Do you feel that more time from the tutor and
more personalized Math Help to identify and fix
the problems faced by your child will help ?

Here is a fool proof solution I strongly recommend
and that too With a minuscule fraction of the amount
you spent on tutors with unconditional 100% money
back Guarantee, if you are not satisfied.

### SUBSCRIBE, TEST, IF NOT SATISFIED, RETURN FOR FULL REFUND

It is like having an unlimited time from an excellent Tutor.

It is an Internet-based math tutoring software program
that identifies exactly where your child needs help and
then creates a personal instruction plan tailored to your
child’s specific needs.

If your child can use a computer and access
the Internet, he or she can use the program.
And your child can access the program anytime
from any computer with Internet access.

### Unique program to help improve math skills quickly and painlessly.

There is an exclusive, Parent Information Page provides YOU
with detailed reports of your child’s progress so you can
monitor your child’s success and give them encouragement.
These Reports include

• Time spent using the program
• Assessment results
• Personalized remediation curriculum designed for your child
• Details the areas of weakness where your child needs additional help
• Provides the REASONS WHY your child missed a concept
• List of modules accessed and amount of time spent in each module
• Quiz results
• Creates reports that can be printed and used to discuss issues with your child’s teachers
These reports are created and stored in a secure section
of the program, available exclusively to you, the parent.
The section is accessed by a password that YOU create and use.
No unauthorized users can access this information.

### Personalized remediation curriculum designed for your child

Thus The features of this excellent Tutoring program are

• Using detailed testing techniques
• Identifing exactly where a student needs help.
• Its unique, smart system pinpointing precise problem areas -
• slowly and methodically guiding the student
• raising to the necessary levels to fix the problem.

### Not a “one-size-fits-all” approach!

Its research-based results have proven that
it really works for all students! in improving
math skills and a TWO LETTER GRADE INCREASE in
math test scores!,if they invest time in using
the program.

Proven for More than 10,000 U.S. public school
students who increased their math scores.