If two or more algebraic expressions are multiplied, their product is obtained.
Each of the algebraic expressions which are multiplied to form the product
are called the Factors (or Divisors) of the product.
Example: We have
(x + a)(x + b) = x2 + x(a + b) + ab
Each of (x + a) and (x + b) are called the factors of x2 + x(a + b) + ab
Factorization of Polynomials :
In Polynomials, we learnt how to multiply two Polynomials.
Can we reverse this process ? i.e. given a polynomial, can we
find two or more polynomials whose product
is equal to the given polynomial.
If we can, the process of doing this is called
Factorization of Polynomials.
Thus,
Factorization of Polynomials means to express a polynomial
as product of two or more polynomials. These two or more
polynomials whose product is equal to the given polynomial
are called the factors (divisors) of the polynomial. This is the reverse
process of multiplication.
Algebra Factoring deals with Factorization of Polynomials.
Prime Polynomial :
A Polynomial is said to be prime if it is divisible by one and itself only.
Prime Polynomials are analogous to Prime
Numbers in the set of Positive Integers. e.g. 3x + 4, 2x2 + 3y2, 2 are prime Polynomials.
Finding the factors of a polynomial
means finding all prime factors.
This is what we do in Algebra Factoring.
Common Factor :
A polynomial (constant polynomial or any degree polynomial)
which divides all the terms of a polynomial is called a Common Factor
of the terms of the Polynomial.
Highest Common Factor (H.C.F.) :
The largest polynomial (constant polynomial or any degree polynomial)
which divides all the terms of a polynomial is called the Highest Common Factor (H.C.F.)
of the terms of the Polynomial.
Factoring a Polynomial using H.C.F. :
A method of factorising a polynomial
is to find the H.C.F. of all the
terms of the polynomial and taking
it out as a common factor.
Let us see some examples.
Example 1 of Algebra Factoring : Factoring using H.C.F.
Factorize 9x3y2 + 3xy2z + 6x3y2z2
Solution:
Looking at all the terms, we can see the largest common term is 3xy2 ∴ H.C.F. = 3xy2
Taking this out, the given expression becomes
3xy2(3x2 + z + 2x2z2)
Thus the two factors of the given expression are
3xy2 and (3x2 + z + 2x2z2).
Thus, Algebra Factoring of 9x3y2 + 3xy2z + 6x3y2z2 using H.C.F. gave factors as 3xy2 and (3x2 + z + 2x2z2). Ans.
Example 2 of Algebra Factoring : Factoring using H.C.F.
Factorize (4a - 3b)(x - 2y) - (3a - b)(x - 2y)
Solution:
Let A = (4a - 3b)(x - 2y) - (3a - b)(x - 2y)
Here we can see (x - 2y) is the H.C.F. Taking this out, we get
A = (x - 2y){(4a - 3b) - (3a - b)} = (x - 2y){4a - 3b - 3a + b)}
= (x - 2y)(a - 2b)
Thus (x - 2y) and (a - 2b) are the two factors for the given expression.
Thus, Algebra Factoring of (4a - 3b)(x - 2y) - (3a - b)(x - 2y) using H.C.F.
gave Factors as (x - 2y) and (a - 2b). Ans.
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