Find the quotient and the remainder
when 97 is divided by 7.
Also check your result.
Solution to the division Problem:
Step1 :
Here, we first find a number which
when multiplied by 7 is near to 9
(not 97 because 9 is bigger than 7. ).
We know 1 x 7 = 7 is near 9. we write 1
in the right bracket and 7 below 9.
7 subtracted from 9 gives 2.
Dividend
Divisor 7 ) 97 ( 1
7
---
2
You may note that
In division either at the end or
at any stage the remainder should
always be less than the divisor.
Step2 :
To the right of this 2, we descend
the next (last) digit 7 in the
dividend to make it 27.
Now we try to find a number which
when multiplied by 7 is near to 27.
We know 3 x 7 = 21 is near 27.
We write 3 in the right bracket to
the right of 1 and 21 below 27.
21 subtracted from 27 gives 6.
As there is no other digit left
in the dividend to descend,
6 is the remainder.
Step1 :
Here, first digit of dividend is 1
which is less than the divisor 3.
So we see the first two digits
of the dividend which is 12.
We find how many times 3 divides 12.
We know 4 x 3 = 12. We put 4 in the
right bracket and 12 below 12 of the
dividend. 12 subtracted from 12 gives 0.
Dividend
Divisor 3 ) 124 ( 4
12
---
0
Step2 :
We descend the next (last) digit
of the dividend, 4 to the right of 0
to make it 04. We know 3 divides 4,
one time. 1 x 3 = 3. We write 1 in the
right bracket after 4 and 3 below 04.
3 subtracted from 4 gives 1
which is the remainder.
Step1 :
Here first digit of dividend is 2
which is less than the divisor 9.
So we see the first two digits
of the dividend which is 24.
We find how many times 9 divides 24.
We know 2 x 9 = 18.
(Note that 3 x 9 = 27 exceeds 24.)
We put 2 in the right bracket and
18 below 24 of the dividend.
18 subtracted from 24 gives 6.
Dividend
Divisor 9 ) 2479 ( 2
18
-----
6
Step2 :
We descend the next digit of the
dividend, 7 to the right of 6 to
make it 67. We know 9 divides 67,
seven times. 7 x 9 = 63.
(Note that 8 x 9 = 72 exceeds 67.)
We write 7 in the right bracket
after 2 and 63 below 67.
63 subtracted from 67gives 4.
Step3 :
We descend the next (last) digit of
the dividend, 9 to the right of 4
to make it 49. We know 9 divides 49,
five times. 5 x 9 = 45.
(Note that 6 x 9 = 54 exceeds 49.)
We write 5 in the right bracket
after 27 and 45 below 49. 45 subtracted
from 49 gives 4 which is the remainder.
Find the quotient and the remainder in the following Division Problems.
97 ÷ 2
138 ÷ 5
3791 ÷ 6
87341 ÷ 7
102109 ÷ 9
101 ÷ 3
3751 ÷ 4
30869 ÷ 8
98765 ÷ 9
4895 ÷ 8
For Answers see at the bottom of the page.
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Answers to Exercise on Division Problems
Answers to Division Problems :
quotient = 48, remainder = 1;
quotient = 27, remainder = 3
quotient = 631, remainder = 5;
quotient = 12477, remainder = 2
quotient = 11345, remainder = 4;
quotient = 33, remainder = 2
quotient = 937, remainder = 3;
quotient = 3858, remainder = 5
quotient = 10973, remainder = 8;
quotient = 611, remainder = 7
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