Find the quotient and the remainder when 97 is divided by 7. Also check your result.
Solution to the division Problem:
Step1 : Here, we first find a number which when multiplied by 7 is near to 9 (not 97 because 9 is bigger than 7. ). We know 1 x 7 = 7 is near 9. we write 1 in the right bracket and 7 below 9. 7 subtracted from 9 gives 2.
Divisor 7 ) 97 ( 1
You may note that In division either at the end or at any stage the remainder should always be less than the divisor.
Step2 : To the right of this 2, we descend the next (last) digit 7 in the dividend to make it 27.
Now we try to find a number which when multiplied by 7 is near to 27.
We know 3 x 7 = 21 is near 27. We write 3 in the right bracket to the right of 1 and 21 below 27. 21 subtracted from 27 gives 6.
As there is no other digit left in the dividend to descend, 6 is the remainder.
Step1 : Here, first digit of dividend is 1 which is less than the divisor 3. So we see the first two digits of the dividend which is 12. We find how many times 3 divides 12. We know 4 x 3 = 12. We put 4 in the right bracket and 12 below 12 of the dividend. 12 subtracted from 12 gives 0.
Divisor 3 ) 124 ( 4
Step2 : We descend the next (last) digit of the dividend, 4 to the right of 0 to make it 04. We know 3 divides 4, one time. 1 x 3 = 3. We write 1 in the right bracket after 4 and 3 below 04. 3 subtracted from 4 gives 1 which is the remainder.
Step1 : Here first digit of dividend is 2 which is less than the divisor 9. So we see the first two digits of the dividend which is 24. We find how many times 9 divides 24. We know 2 x 9 = 18. (Note that 3 x 9 = 27 exceeds 24.) We put 2 in the right bracket and 18 below 24 of the dividend. 18 subtracted from 24 gives 6.
Divisor 9 ) 2479 ( 2
Step2 : We descend the next digit of the dividend, 7 to the right of 6 to make it 67. We know 9 divides 67, seven times. 7 x 9 = 63. (Note that 8 x 9 = 72 exceeds 67.) We write 7 in the right bracket after 2 and 63 below 67. 63 subtracted from 67gives 4.
Step3 : We descend the next (last) digit of the dividend, 9 to the right of 4 to make it 49. We know 9 divides 49, five times. 5 x 9 = 45. (Note that 6 x 9 = 54 exceeds 49.) We write 5 in the right bracket after 27 and 45 below 49. 45 subtracted from 49 gives 4 which is the remainder.
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Answers to Exercise on Division Problems
Answers to Division Problems :
quotient = 48, remainder = 1;
quotient = 27, remainder = 3
quotient = 631, remainder = 5;
quotient = 12477, remainder = 2
quotient = 11345, remainder = 4;
quotient = 33, remainder = 2
quotient = 937, remainder = 3;
quotient = 3858, remainder = 5
quotient = 10973, remainder = 8;
quotient = 611, remainder = 7
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