Simple Quadratic Polynomial as Product of Two Factors:
x2 + x(a + b) + ab = (x + a)(x + b)
Formula 11 in Factoring Special Products :
General Quadratic Polynomial as Product of Two Factors:
acx2 + x(ad + bc) + bd = (ax + b)(cx + d)
Observing these two Formulas, we can say that if the numerical product of the cofficient of x2 and constant term be expressed as two numerical factors such that their sum is equal to the coefficient of x, then we can write the factors of the Quadratic Polynomial.
This leads us to a method.
Method of Factoring Trinomials (Quadratics)
Step 1 :
Multiply the coefficient of x2 by the constant term.
Step 2 :
Resolve this product into two factors such that their sum is the coefficient of x
Step 3 :
Rewrite the x term as the sum of two terms with these coeffiecients.
Step 4 :
Then take the common factor in the first two terms and the last two terms.
Step 5 :
Then take the common factor from the two terms thus formed. What you get in step 5 is the product of the required two factors.
The method will be clear by the following Soved Examples.
Example 1 of Factoring Trinomials (Quadratics)
Factorize 9x2 + 26x + 16
Solution to Example 1 of Factoring Trinomials (Quadratics) :
Let P = 9x2 + 26x + 16
In Factoring of Trinomials (Quadratics) , follow the five steps listed above.
Step 1: Coefficient of x2 x constant term = 9 x 16 = 144
Step 2: We have to express 144 as two factors whose sum = coefficient of x = 26; 144 = 2 x 72 = 2 x 2 x 36 = 2 x 2 x 2 x 18 = 8 x 18; (8 + 18 = 26)
Step 3: P = 9x2 + 26x + 16 = 9x2 + 8x + 18x+ 16
Step 4: P = x(9x + 8) + 2(9x + 8)
Step 5: P = (9x + 8)(x + 2)
Thus, Applying the Method of Algebra Factoring of Quadratic Polynomial to 9x2 + 26x + 16, we get the Factors as (9x + 8)(x + 2) Ans.
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