In practice, instead of taking the entire part of the decimal part, we take the approximate value. we some times take the whole number nearest to the decimal number.

Some times, we may take the value nearest to one or two or three or more decimal places.

Depending on the intended purpose, we take an approximate value of the decimal number.

Rounding Decimals

The process of obtaining the value of a decimal correct to the required number of decimal places is called rounding and the value obtained is called the rounded or corrected value of the decimal.

Rounding Decimals to the nearest whole number :

Method :

Step 1 : Retain all the digits of the whole number part and omit the decimal part.

Step 2 : Out of the omitted decimal part, if the first digit to the right of the decimal point is 5 or more, then increase the number formed from the retained digits by 1, otherwise do not make any change.

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Rounding Decimals to the required number of decimal places

Method :

Step 1 : Retain as many digits after the decimal point as are required and omit the remaining digits.

Step 2 : Out of the omitted decimal part, if the first digit to the right of the decimal point is 5 or more, then increase the last retained digit by 1, otherwise do not make any change.

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Examples on Rounding Decimals to the required number of decimal places :

Round off

9.1347, correct to 3 decimal places (or to thousandths' place.)

5.732, correct to 1 decimal place (or to tenths' place.)

0.047, correct to 2 decimal places (or to hundredths' place.)

Solution : (i) 9.1347, correct to 3 decimal places. We retain 3 digits of the decimal part in 9.1347 to get 9.134 and omit the digit 7.

The first omitted digit is 7 > 5.

So, we increase the last retained digit (4) by 1 ( i.e. make it 5).

∴ Required Number = 9.135 Ans.

(ii) 5.732, correct to 1 decimal place. We retain 1 digit of the decimal part in 5.732 to get 5.7 and omit the digits 3 and 2.

The first omitted digit is 3 < 5.

So, we do not make change to the retained digits.

∴ Required Number = 5.7 Ans.

(iii) 0.047, correct to 2 decimal places. We retain 2 digits of the decimal part in 0.047 to get 0.04 and omit the digit 7.

The first omitted digit is 7 > 5.

So, we increase the last retained digit (4) by 1 ( i.e. make it 5).

∴ Required Number = 0.05 Ans.

Exercise on Rounding Decimals

Round off to the nearest whole number.

197.351

42.78

231.51

Round off

7.6428, correct to 3 decimal places (or to thousandths' place.)

9.157, correct to 1 decimal place (or to tenths' place.)

0.451, correct to 2 decimal places (or to hundredths' place.)

For Answers see at the bottom of the page.

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